package main
func f(vs ...interface{}) {
print(len(vs))
}
func main() {
f()
f(nil)
f(nil...)
}
Choices:
Answer: It prints 0 1 0.
Run it on Go play.
Key points:
nil in f(nil...) is treated as a nil slice (of type []interface{}).
nil in f(nil) is treated as an element in a slice.
The call f(nil) is equivalent to f([]interface{}{nil}...).
f() is equivalent to f(nil...).
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