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slice 1

What does the following program print?

package main

import "fmt"

func main() {
	a := [...]int{0, 1, 2, 3}
	x := a[:1]
	y := a[2:]
	x = append(x, y...)
	x = append(x, y...)
	fmt.Println(a, x)
}

Choices:

Answer: [0 2 3 3] [0 2 3 3 3]

Run it on Go play.

Key points:
  • Initially, the slice y is [2 3], and the slice x is [0] with three free element slots (in other words, its capacity is 4),
  • The 1st append call changes the slice x to [0 2 3] with one free element slot. And as the slice x and the array a share elements (before line 10), the array a is changed to [0 2 3 3]. The slice y and the array a also share elements, so the slice y is changed to [3 3].
  • For the slice x has not enough free capacity, the 2nd append call allocates a new backing array for the slice x. So the call doesn't modify the array a. The slice x is changed to [0 2 3 3 3].


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