package main
type A struct {
g int
}
func (A) m() int {
return 1
}
type B int
func (B) g() {}
func (B) f() {}
type C struct{
A
B
}
func (C) m() int {
return 9
}
func main() {
var c interface{} = C{}
_, bf := c.(interface{f()})
_, bg := c.(interface{g()})
i := c.(interface{m() int})
println(bf, bg, i.m())
}
Choices:
Answer: true false 9
Run it on Go play.
Key points:
C.A.g and method C.B.g collide, so they are both not promoted.
C.B.f gets promoted as C.f.
C.m overrides C.A.m.
Please read type embedding for more detailed explanations.
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